1860 Chicago mayoral election
Election
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In the Chicago mayoral election of 1860, Democratic nominee John Wentworth defeated Republican nominee Walter S. Gurnee.
Both candidates had served as mayor before. Incidentally, each had previously been mayor under the opposite party affiliation. Gurnee had served two terms as a Democrat, having been elected in 1851 and 1852, Wentworth had previously served one term as a Republican, having been elected in 1857.
The election was held on March 3.[1]
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic | John Wentworth | 9,998 | 53.36 | |
Republican | Walter S. Gurnee | 8,739 | 46.64 | |
Turnout | 18,737 |
References
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